题目链接:
https://www.nowcoder.com/practice/04a5560e43e24e9db4595865dc9c63a3
解法分析:纯的层序遍历,使用 BFS
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function levelOrder(root) { if (!root) { return []; } const res = [], queue = []; queue.push(root);
while (queue.length) { const currentLevelSize = queue.length; res.push([]); for (let i = 0; i < currentLevelSize; i++) { const node = queue.shift(); res[res.length - 1].push(node.val);
node.left && queue.push(node.left); node.right && queue.push(node.right); } } return res; }
module.exports = { levelOrder : levelOrder };
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