题目链接:https://leetcode-cn.com/problems/lru-cache/  解法分析:LRU 经典模拟题,使用双链表 + 哈希组合的方法解决。
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 var  DoubleLinkedListNode = function (key, value )  {    this .key = key;     this .value = value;     this .prev = null ;     this .next = null ; } var  LRUCache = function (capacity )  {    this .capacity = capacity;     this .map = new  Map ();          this .dummyHead = new  DoubleLinkedListNode(null , null );     this .dummyTail = new  DoubleLinkedListNode(null , null );     this .dummyHead.next = this .dummyTail;     this .dummyTail.prev = this .dummyHead; }; LRUCache.prototype._isFull = function ( )  {     return  this .map.size === this .capacity; } LRUCache.prototype._removeNode = function (node )  {     node.prev.next = node.next;     node.next.prev = node.prev;          node.prev = null ;     node.next = null ;     return  node; } LRUCache.prototype._addToHead = function (node )  {     const  head = this .dummyHead.next;     node.next = head;     head.prev = node;     node.prev = this .dummyHead;     this .dummyHead.next = node; } LRUCache.prototype.get = function (key )  {     if  (this .map.has(key)) {                  const  node = this .map.get(key);         this ._addToHead(this ._removeNode(node));         return  node.value;     } else  {         return  -1 ;     } }; LRUCache.prototype.put = function (key, value )  {     if  (this .map.has(key)) {                  const  node = this .map.get(key);         node.value = value;         this ._addToHead(this ._removeNode(node));     } else  {         if  (this ._isFull()) {                          const  node = this .dummyTail.prev;             this .map.delete(node.key);             this ._removeNode(node);         }                  const  node = new  DoubleLinkedListNode(key, value);         this .map.set(key, node);         this ._addToHead(node);     } };